进入函数时，取 TickType_txStart = xTaskGetTickCount();之后，利用 xTaskGetTickCount() 与 xStart 的差值，判断函数运行是否超时
2020-06-11 09:00
我写了个程序想通过xTaskGetTickCount()函数来获得按键被按下去的时间长度，程序很简单： if(Key_Scan(KEY1_GPIO_PORT,KEY1_PIN)==KEY_ON
2020-07-27 22:46
sem, u32_t timeout){portTickType StartTime, EndTime, Elapsed; StartTime = xTaskGetTickCount
2019-07-16 22:28
, end_time = 0,diff = 0;initial_time = xTaskGetTickCount();while(1){ HAL_GPIO_WritePin(GPIOD
2023-01-30 06:03
){TickType_t t = xTaskGetTickCount();//单位10ms/* write back */for (size_t i = 0; i < size;) {size_t
2024-06-05 06:22
){TickType_t timestamp;while(1){ //lpt_profiler; timestamp = xTaskGetTickCount() * portTICK_PERIOD_MS; while
2022-12-06 06:00
;TickType_t xLastWakeTime;const TickType_t xFrequency = 5;//msxLastWakeTime = xTaskGetTickCount
2020-06-11 09:00
= 0; } // 长按 TS0 快速减10 if (e0 == TOUCH_LONG_PRESS && xTaskGetTickCount
2025-06-16 22:28
TickType_t xTicksToWait = 50 / portTICK_PERIOD_MS; /* 延迟50ms */xLastWakeTime=xTaskGetTickCount();//获取当前心跳值
2017-03-08 15:23
;portTickTypexLastExecutionTime, xDelayTime; xLastExecutionTime= xTaskGetTickCount();xDelayTime= (1 <
2016-12-11 13:59
