:{ItasyListDe=;.*(.Currest.Actult.*)*(.PBSS.PBSS.*)= AlcIn(4);yTrimeEngult=;} & kSG1L1DATA.MeSO
2018-12-28 15:45
关于数Gpbs高速存储器接口设计的分析,看完你就懂了
2021-05-19 06:38
亲爱的各位,我有一个很傻的问题。我增加了一个分压器,把电压从20V降到1.6V,所以用A:PIC PIC16F1527来定量0.83IAM。电阻是82.5K和7.5K,PIN 45 ADC通道AN2020,我观察到:当我把分压器的输出连接到PIC时,VARTA。Ge在输出分压器上增加了0.5V以上,增加了缓冲器,仍然增加了0.2V。假设5V而不是20V,VOUT分压器的输出为0.41。但是当我连接到PIC时,它会移动到1.11V。如果我添加一个缓冲器,它会移动到0.62VS,它可以在没有使用软件的情况下清除100%吗?谢谢你的帮助,安东尼奥 以上来自于百度翻译 以下为原文 Dear all, I have a very silly question. I have add a voltage divider to drop down my voltage from 20V to 1.6V so a ration of 0.83 I am using a: PICPIC16F1527 the resistor is 82.5k and 7.5k , Pin 45 ADC channel AN_20 What I have observed: when i connect the output of voltage divider to the PIC the voltage on the output voltage divider increases more than 0.5V. Adding a buffer it still increasing of 0.2V. Assuming 5V instead of 20V the output of Vout voltage divider is 0.41. but when i connect to the PIC it shifts up to 1.11V. If i add a buffer it shifts up to 0.62V Is it any way to clear at 100% without using software? Thank you for your help Cordially Antonio
2019-04-04 15:57
植入产品的定义是什么?可植入材料可以分为哪几类?可植入材料有哪些应用?
2021-07-09 06:16