论坛的大神是否有单周期控制的VIENNA整流器saber仿真电路,可以发给我学习下吗
2017-05-24 09:07
请问大家有单周期控制的VIENNA整流器的simulink仿真文件吗?
2019-04-15 17:45
Vienna-5G-LL仿真器是什么?Vienna-5G-LL仿真器的结构是如何构成的?Vienna-5G-LL仿真器有哪些特性?
2021-06-21 07:57
最近在调试三相四线制VIENNA整流器,使用的是单周期控制,由于使用的三相四线制,所以先先单独调试了一相,在轻载状态下,调压器输入电压升到170Vac时,输出就能够稳定在700Vdc了,但是输入电压继续往上调时,输入电流出现大幅度抖动,想请教一下各位这是什么原因引起的呢?有什么好的方法去解决?
2019-05-22 10:12
AMC1301你好,我在看三相VIENNA的原理图时候,遇到个问题,如下图 在计算电阻分压的增益时候,假设VPM=300V,那么通过电阻R94 R95 R97和R100电阻分压,得到的增益应该
2024-08-08 08:26
作者:Nagarajan Sridhar每当与人谈及电动汽车(EV)时,我经常会听到这样的观点:电动汽车的续航里程不够长,难以行驶很远的距离。虽然特斯拉和一些其他汽车厂商推出了行驶距离超过200英里的车辆,但上述问题在很大程度上是确实存在的。与此同时,还有另一个障碍大大削弱了电动汽车的吸引力,即充电站的缺乏。等到充电站像加油站一样随处可见的时候,电动汽车才能在市场中普及开来。
2019-07-15 06:56
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2017-11-03 10:55
Alexey Shuvaev, Andrei Pimenov, Florian Aigner, Georgy Astakhov, Mathias Mühlbauer, Christoph Brüne, Hartmut Buhmann and Laurens W. Molenkamp通过导通光学晶体改变栅极电压可以改变透过拓扑绝缘体薄膜的THz光的偏振方向。今天的计算机,信息是通过电荷处理的。基于固有的物理限制,通过电子晶体管的减少来提高计算机处理速度面临巨大的挑战。突破这些限制的一个途经是用光来替代电流。为使此法可行,我们需要有效的操作工具。
2019-05-28 06:24
亲爱的社区,我一直与ADC D-S的PSoC5LP没有成功地放大2个divand信号与5MVPP最大。我读过不同的文件,对此我感到很困惑。在ADC Delta Sigma 3.30参考文献的第9页中,输入±VREF与VREF=1.024V的范围应该是:- 1.024±1.024=0V至2.048。为什么在相同条件下的CE95171上,在ADC的负引脚上VREF=1.024,在第2页中,如果ADC的正输入为0,转换值为-1.024或如果为1.024,则值为0;因此,ADC Delta Sigma 3.30的页9建立的范围不从0V到2.048。然后,工作范围可以支持直到2.048 V作为一个有效的值来工作吗????2.048?gt;1.024V?或者我甚至可以输入3V信号根本没有问题?VDD=5V?这是非常混乱的,请您提供任何帮助,我会非常感激,谢谢。 以上来自于百度翻译 以下为原文Dear community, I have been working with ADC D-S of psoc5lp with no success to amplify 2 diferential signals with 5mVpp as maximum. I have read different documents and I'm very confused about this. In page 9 of reference document of ADC Delta-Sigma 3.30 the range with Input ± Vref with Vref=1.024V should be: -1.024±1.024= 0V to 2.048. Why in example of CE95271 with the same condition Vref=1.024 on negative pin of ADC, in page 2 says that if positive enter of ADC is 0 the converted value is -1.024 or if is 1.024 the value is 0; so the range doesn't go from 0V to 2.048 as page 9 of ADC Delta-Sigma 3.30 established? then the range to work can support until 2.048 V as a valid value to work???? 2.048 -> 1.024V? Or can I even enter 3V signal with no problem at all? with VDD=5V? This is very confused, please any help you can provide me will be very appreciated, thanks in advance.
2018-09-20 16:34
嘿,亲爱的专家们,我的项目定义如下:要求:1)测量无刷转子(南北极S高斯),并在LCD上显示+-值2)在开始时LCD可以偏移到零会很好3)白金版-存储最大值…技术细节霍尔传感器IST用5V馈电,如果没有磁场的影响,则传输约2,3V。1600高斯磁铁有0.5V到4.1V的范围。传感器每高斯给出1,3毫伏。直到现在发生了什么设置LCD为零与电位器一起工作,但是如果值在零LCD下显示16位代码的正值65535。我的问题到目前为止:1)有一个很好的硬件解决方案来满足我的要求,因此我对此太愚蠢了。在第8页上的SAR解密显示了很多“单端结果格式”,在这个项目上,我不能在我的吨版本中匹配。2)软件解决方案-意义-读取霍尔传感器的起始值-将其存储在寄存器或变量中,然后从测量中减去它。提前致以最良好的问候和感谢哈利对不起,我的电子设备是30年前的,我从来没有玩过微控制器,但是我喜欢这些小东西,它们比我聪明。HALLYPSO44V4-0.0.CYWRK.SARVEVE01.ZIP1.3兆字节 以上来自于百度翻译 以下为原文Hey dear specialists,my project is defined as follow: requirements:1) Measure brushless rotor (north south pole´s gauss) and showing+-value on LCD2) would be fine that LCD can offset to zero at the beginning3) platinum version --storage max values..... technical detailsHall sensor ist feeded with 5V and deliver about 2,3V if there is no influens with magnetic field.with 1600 gauss magnet there is a range of 0.5V to 4.1V.the sensor give 1,3mVolt per gauss what happen until now set LCD to zero is working with potentiometer, but if value goes under zero LCD show a positive value 65535 of a 16 bit code. My question so far:1) is there a nice hardware solution to fulfill my requirements, hence im too stupid for this SAR decription on page 8 shows a lot of "single ended result formats", which I´m not able to match in my tons of versions on this project 2) software solution- meaning-read start value of Hall sensor -storage it in a register or variable then subtract it from the measurement- very best regards and thanks in advanceHarry sorry my electronics are 30 years ago and i never played with micro controller, but i HAVEFUN with this small things, which are smarter than ME Hall_PSOC4_V4-000.cywrk.Archive01.zip 1.3 MB
2018-09-19 10:57