SD卡问题：r1=SPIx_ReadWriteByte(0xFF)；表示啥意思？
2020-06-04 09:50
SPIx_ReadWriteByte(W25X_ReadStatusReg); //发送读取状态寄存器命令 byte=SPIx_ReadWriteByte(0Xff); //读取一个字节 SPI_FLASH_CS=1; //取消
2019-10-14 22:04
//等待卡准备好//返回值:0,准备好了;其他,错误代码u8 SD_WaitReady(void){ u32 t=0; do { if(SPIx_ReadWriteByte(0XFF)==0XFF)return 0;//OKt++; }while(t
2019-11-06 01:09
SPIx_ReadWriteByte(W25X_ReadData);//发送读取命令 SPIx_ReadWriteByte((u8)((ReadAddr)>>16));//发送24bit
2020-05-29 09:31
(VS_DQ==0);//等待空闲 SPIx_ReadWriteByte(0X00);//启动传输 retry=0; VS10XX_ID=VS_RD_Reg(SPI_STATUS);//读取状态寄存器
2019-08-30 04:35
uint32_t SPI_RW_Reg(uint16_t CofigReg) { delay(10); readata1=SPIx_ReadWriteByte((uint8_t
2025-01-13 07:03
NRF24L01_Write_Reg(u8 reg,u8 value){u8 status;NRF24L01_CSN=0;//使能SPI传输 status =SPIx_ReadWriteByte(reg
2020-05-20 05:27
驱动gd25q40b程序是参考正点原子的w25x16，发现两个芯片差不多，但是在读id的时候发现一个问题，把原子哥的读写函数返回字节改成u16，如下u16SPIx_ReadWriteByte(u8
2018-09-05 09:29
DacData) { SPI_DAC_CS=0; SPIx_ReadWriteByte(SPI1 , (u8)(DacData) >> 8); SPIx_ReadWriteByte(SPI1 , (u8)DacData); delay
2025-01-22 07:15
采样子程序#include "public.h"u8 SPIx_ReadWriteByte(u8 TxData);void RCC_Configuration(void);void
2018-11-28 09:00
