for the noise contribution of Spectrum analyzer vs the Signal to noise ratio. For example whenthe S/N is 10
2019-07-18 08:53
require :- high performance- low power- low cost ( if it's possible) I will be grateful for your contribution. Charko PS: sorry for my bad english !
2019-01-10 11:15
在AD7609的手册16页，有相关图表。但不明白NFS和PFS是什么
2019-01-11 09:20
哪些参数会影响SNR？哪种评估SNR最好？以上来自于谷歌翻译以下为原文 Which are the parameters that impact on SNR? Which is the best way to evaluate the SNR?
2018-09-28 16:47
您好，我有一台HP8648D S / N 3613A00395，只要RF打开，它就会在LCD上显示PULSE。该装置没有也没有安装脉冲选件。除此之外，该单元出现在校准中并且工作正常。知道为什么会这样吗？ Sam W3OHM 以上来自于谷歌翻译 以下为原文Hello, I have a HP8648D S/N 3613A00395 that displays PULSE on the LCD whenever the RF is turned ON. This unit does not have nor has it had the pulse option installed. Other than this the unit appears in calibration and works correctly. Any idea why this might be happening? Sam W3OHM
2018-10-19 11:38
什么是反存储效应电路？如何在3级/ CW配置的情况下如何提高性能？ #ultrasound以上来自于谷歌翻译以下为原文 what is the anti-memory effect circuit and how does it benefit performance in case of 3-level/CW configuration?#ultrasound
2019-04-17 16:31
我正在尝试使用N5531S（选择550传感器）测量接收器系统测量0到-130dBm的绝对功率水平，然后计算它的不确定性。安捷伦的应用笔记已经提到，不确定度可以使用公式+/-计算（功率计范围2-4 + 0.005dB / 10dB步长），但是有些注意事项也提到累积误差也应该考虑到？我现在对我的不确定性预算应考虑的公式和不确定因素有点困惑。 以上来自于谷歌翻译 以下为原文I'm trying to measure 0 to -130dBm absolute power level using N5531S (opt. 550 sensor) measuring reciver system and then calculate uncertainty for it. Agilent application notes has mentioned that uncertainty can be calculate using the formula +/-(power meter range 2-4 + 0.005dB/10dB step), but some notes has mentioned about cumulative errors too which should take account? I'm little bit confused now what formulas and uncertainty things i should take account for my uncertainty budget.
2019-02-19 15:40
如何对Android7.1 RK3288 Thermal进行控制呢？
2022-03-04 06:29
有人能解释为什么当VDAC输出被设置为零时，它的输出电压不是零伏特？当VDAC设置为0时，我的测试显示电压为1.4MV。这仅仅是来自组件中使用的缓冲区的电压偏移吗？我不确定VDAC的确切设计，但我知道它是基于IDAC的。 以上来自于百度翻译 以下为原文Can someone explain why the VDAC output is not zero volts when it is set to zero? My test showed a voltage of 1.4mV when I set the VDAC to zero. Is this simply a voltage offset orginating from a buffer used in the component? I'm not sure of the exact design of the VDAC, but I do know that it is based on the IDAC.
2019-02-20 15:00
这一次，实际上，不久前，我偶然发现了一个热敏电阻的样本项目。虽然电路似乎很容易，但计算并不像我预期的那么容易。根据热敏电阻的网页，我们可以计算出热敏电阻的电阻如下方程。RT：在温度T（K）的阻力R0：T0电阻B：热敏电阻相关的常数。对于103AT-11，它是3435±1%。转换从TK（Kelvin）Tc（摄氏度）是TC = TK - 273.15除双方通过R0，我们得到替换E到日志用B分隔两边从数据表该热敏电阻的电阻值10.0k在25摄氏度，所以如果我们更换R0 R25和T0 T25（克列温为25C）方程是现在移动1 / T25从右至左左侧缩小然后根据改革方程最后我们得到在下面的图中RT＝R1 x VT/（VDDA -VT）如果我们正常的ADC值（ADin）输入电压0V ~ VDDA V至0 ~ 1RT＝R1 x AdIn／（1 -埃丁）现在我们可以编写一个代码RT＝R1*ADIN／（1 -埃丁）；K = 1 /（log（RT / R25）/ B＋1／T25）；t＝K－273.15；长话短说，这就是全部！（AKA，附上的项目）摩托罗拉tempsensor180422.cyprj.archive01.zip542.6 K 以上来自于百度翻译 以下为原文This time, actually a while ago, I came across a chance to make a sample project of thermistor.Although the circuit seemed to be easy, the calculation was not as easy as I was expecting.According to the web page of the thermistor, we can calculate the resistance ofa thermistor with following equation. Rt : Resistance at temperature t (kelvin)R0: Resistance at T0B: Thermistor related constant. For 103AT-11 it is 3435 +/- 1%Conversion from Tk (Kelvin) to Tc (Celsius) is Tc = Tk - 273.15 Dividing both sides by R0, we get Replacing e to logDividing both sides by BFrom the Datasheet the resistance value of this thermistor is 10.0K at 25 degree Celsius,so if we replace R0 to R25 and T0 to T25 (Klevin for 25c) the equationis nowMoving 1/T25 from the right side to the left sideReducing the left sideThen reforming the equation according to TFinally we get In the figure below Rt = R1 x Vt / (VDDA -Vt) If we normalize the ADC value (ADin)of input voltage 0V ~ VDDA V to 0.0 ~ 1.0 Rt = R1 x ADin / (1 - ADin) Now we can write a code Rt = R1 * ADin / (1 - ADin) ;K = 1.0 / (log(Rt / R25) / B + 1.0/T25) ;T = K - 273.15 ; To make the long story short, here is the whole enchilada!(aka, project attached...) moto TempSensor180422.cyprj.Archive01.zip 542.6 K
2018-09-04 15:04
